(2k^2-4k+5)=0

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Solution for (2k^2-4k+5)=0 equation:


Simplifying
(2k2 + -4k + 5) = 0

Reorder the terms:
(5 + -4k + 2k2) = 0

Remove parenthesis around (5 + -4k + 2k2)
5 + -4k + 2k2 = 0

Solving
5 + -4k + 2k2 = 0

Solving for variable 'k'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
2.5 + -2k + k2 = 0

Move the constant term to the right:

Add '-2.5' to each side of the equation.
2.5 + -2k + -2.5 + k2 = 0 + -2.5

Reorder the terms:
2.5 + -2.5 + -2k + k2 = 0 + -2.5

Combine like terms: 2.5 + -2.5 = 0.0
0.0 + -2k + k2 = 0 + -2.5
-2k + k2 = 0 + -2.5

Combine like terms: 0 + -2.5 = -2.5
-2k + k2 = -2.5

The k term is -2k.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2k + 1 + k2 = -2.5 + 1

Reorder the terms:
1 + -2k + k2 = -2.5 + 1

Combine like terms: -2.5 + 1 = -1.5
1 + -2k + k2 = -1.5

Factor a perfect square on the left side:
(k + -1)(k + -1) = -1.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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